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(2x+1)+(2x+1)+(2x^2+5x-4)=0
We get rid of parentheses
2x^2+2x+2x+5x+1+1-4=0
We add all the numbers together, and all the variables
2x^2+9x-2=0
a = 2; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·2·(-2)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{97}}{2*2}=\frac{-9-\sqrt{97}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{97}}{2*2}=\frac{-9+\sqrt{97}}{4} $
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